(x^2-x+1)=0

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Solution for (x^2-x+1)=0 equation: 



(x^2-x+1)=0

We get rid of parentheses

x^2-x+1=0

We add all the numbers together, and all the variables

x^2-1x+1=0

a = 1; b = -1; c = +1;
Δ = b2-4ac
Δ = -12-4·1·1
Δ = -3
Delta is less than zero, so there is no solution for the equation

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